3[2(b-7)+5]=45

Solution for 3[2(b-7)+5]=45 equation:

Simplifying
3[2(b + -7) + 5] = 45

Reorder the terms:
3[2(-7 + b) + 5] = 45
3[(-7 * 2 + b * 2) + 5] = 45
3[(-14 + 2b) + 5] = 45

Reorder the terms:
3[-14 + 5 + 2b] = 45

Combine like terms: -14 + 5 = -9
3[-9 + 2b] = 45
[-9 * 3 + 2b * 3] = 45
[-27 + 6b] = 45

Solving
-27 + 6b = 45

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '27' to each side of the equation.
-27 + 27 + 6b = 45 + 27

Combine like terms: -27 + 27 = 0
0 + 6b = 45 + 27
6b = 45 + 27

Combine like terms: 45 + 27 = 72
6b = 72

Divide each side by '6'.
b = 12

Simplifying
b = 12